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6x^2+55x+125=0
a = 6; b = 55; c = +125;
Δ = b2-4ac
Δ = 552-4·6·125
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-5}{2*6}=\frac{-60}{12} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+5}{2*6}=\frac{-50}{12} =-4+1/6 $
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